If he travels twice as far in half the time then he must cycle at 4 times his walking/running pace.
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cycle would cross = example 3 hourswalking would be = 6hoursthereforecycling is 3 times greater than walking
total dist = xtime(cycl) = tthen, time (walk) = 2tdist (cycl) = 2x/3so, speed (cycl) = 2x/3tsimilarly, speed (walk) = x/6tso, his cycl speed is 4 times that of walking!!
If he travels twice as far in half the time then he must cycle at 4 times his walking/running pace.
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ReplyDeletecycle would cross = example 3 hours
ReplyDeletewalking would be = 6hours
therefore
cycling is 3 times greater than walking
total dist = x
ReplyDeletetime(cycl) = t
then, time (walk) = 2t
dist (cycl) = 2x/3
so, speed (cycl) = 2x/3t
similarly, speed (walk) = x/6t
so, his cycl speed is 4 times that of walking!!