January 26, 2011

IQ puzzle


Find a number such that when you rotate the number to the left,
the new number is 1.5 times the original number.

To rotate the number left, move the first digit to the last place
of the number like 75837 rotated to the left is 58377)

8 comments:

  1. André MenesesJanuary 26, 2011 at 5:46 PM

    for (int i = 10; i < int.MaxValue; i++)
    {
    int original = i;
    int shifted = int.Parse(i.ToString().Substring(1) + i.ToString()[0]);

    if ((original * 1.5F) == shifted)
    {
    Console.WriteLine("Original: " + original + "\nShifted: " + shifted);
    break;
    }

    }

    That's how I discovered
    Original: 352941176
    Shifted: 529411763

    ReplyDelete
  2. UnknownJanuary 26, 2011 at 5:53 PM

    @Andre

    Original * 1.5 = Shifted
    but 352941176 * 1.5 = 529411764
    not 529411763

    Just missed !!! :)

    ReplyDelete
  3. CandaceFebruary 14, 2011 at 1:16 AM

    What about 13, 1 rotated to left is 31. which is exactly one whole and a half times the original number. It didn't say it had to be a huge number, correct?

    ReplyDelete
  4. Secret SquïrrelFebruary 17, 2011 at 3:46 PM

    Sorry Candace but 1.5 * 13 = 19.5

    ReplyDelete
  5. AnonymousFebruary 22, 2011 at 11:52 PM

    What is the answer?

    ReplyDelete
  6. AnonymousFebruary 23, 2011 at 12:34 AM

    Zero should be a good answer. It does not ask us to come up with a non-zero number.

    Has it got something to do with decimal places? complex numbers? Or is it just an integer.

    ReplyDelete
  7. AnonymousFebruary 24, 2011 at 12:18 AM

    One of the Numbers iss:

    3529411764705882

    ^^

    ReplyDelete
  8. UnknownMarch 8, 2014 at 10:41 PM

    6 :)

    ReplyDelete