There's 1 Smith, and two others - Jones & Wilson (all but two are Smith). There's 1 Jones, and two others - Smith & Wilson (all but two are Jones). There's 1 Wilson, and two others - Smith & Jones (all but two are Wilson).
It's 3. The mathematical way to find this out would be: Equation: P= s+j+w Key: P= # of people s= # of people named smith j= # of people named Jones w= # of people named wilson So... is all but 2 are named Smith then s= P-2, if all but 2 are named jones then j= P-2, if all but 2 are named wilson then w= P-2
P then eqauls: P= (P-2) + (P-2) + (P-2) P= 3P-6 -2P= -6 P= 3
2...
ReplyDelete3 - one Smith, one Jones and one Wilson.
ReplyDelete3
ReplyDelete3
ReplyDelete3 :P
ReplyDelete3
ReplyDelete3
ReplyDeletetotal 6. 2 smith, 2 jones and 2 wilson
ReplyDeleteonly 2 ..none of them is smith,jones or wilson
ReplyDeleteMust be 3
ReplyDelete6? or 2?
ReplyDelete3 quite easy one
ReplyDeleteIts 3 smith, jones and Wilson
ReplyDeletehow it will be 3
ReplyDeleteA minimum of 3
ReplyDelete3??
ReplyDelete3??
ReplyDelete3
ReplyDeleteexplain pls
ReplyDeleteThere's 1 Smith, and two others - Jones & Wilson (all but two are Smith).
ReplyDeleteThere's 1 Jones, and two others - Smith & Wilson (all but two are Jones).
There's 1 Wilson, and two others - Smith & Jones (all but two are Wilson).
Its 3 smith, jones and Wilson
ReplyDeleteIt's 3. The mathematical way to find this out would be:
ReplyDeleteEquation: P= s+j+w
Key: P= # of people s= # of people named smith j= # of people named Jones w= # of people named wilson
So... is all but 2 are named Smith then s= P-2, if all but 2 are named jones then j= P-2, if all but 2 are named wilson then w= P-2
P then eqauls: P= (P-2) + (P-2) + (P-2)
P= 3P-6
-2P= -6
P= 3
The correct answer is 2 or 3? Can it be 2 considering that none of them is named smith or Jones or Wilson?
ReplyDelete