October 1, 2015

100 employees in a conference room

There are 100 employees in a conference room in New York City. You note that 99% of them are managers. How many managers would need to leave the conference in order to reduce the percentage of managers in the hall to 98%?

4 comments:

  1. David and Anne lymnOctober 1, 2015 at 4:58 PM

    Assuming the outcome requires the percentage to be exactly 98% then 50 would need to go. This leaves 49 plus the one non-manager= 98% are managers

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  2. SuvinthraOctober 1, 2015 at 5:13 PM

    50 members

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  3. UnknownNovember 24, 2015 at 6:33 PM

    how is it 50, when it is told 99% out of 100 employees ?

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    Replies
    1. AnonymousMarch 13, 2016 at 3:51 AM

      But when one leaves there will be 98 out of 99 managers and thats a 98.98%, but if 50 leave then there will be 49 out of 50= 98%

      Delete