tag:blogger.com,1999:blog-3802979373213475425.post7543200345717661214..comments2019-04-20T15:33:02.879+05:30Comments on Critical Thinking Puzzles: Peculiar Number PuzzleUnknownnoreply@blogger.comBlogger5125tag:blogger.com,1999:blog-3802979373213475425.post-7576633724105116132015-10-23T21:47:20.031+05:302015-10-23T21:47:20.031+05:30Yes, 2519
Yes, 2519<br />Jerry Critterhttps://www.blogger.com/profile/01870618647449723147noreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-19362880068821145352015-10-23T13:03:42.383+05:302015-10-23T13:03:42.383+05:30I go with Josh D's answer and explanation : - ...I go with Josh D's answer and explanation : - 2519.Suvinthra Mnoreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-90565610491168655552015-10-23T03:40:13.754+05:302015-10-23T03:40:13.754+05:30I believe the solution is 2,519.
From the first s...I believe the solution is 2,519.<br /><br />From the first statement, having a remainder of 1 means it is one less than an number divisible by 2.<br />From the second statement, having a remainder of 2 means it is one less than a number divisible by 3.<br />From the third statement, having a remainder of 3 means it is one less than an number divisible by 4.<br />..etc... for the rest of the statements.<br /><br />This means that it is one less than a number that is divisible by 2,3,4,5,6,7,8,9,10. That means we need the Least-Common-Multiple (LCM) of those nine numbers.<br /><br />Getting the prime factorization of each of those numbers.<br />2 = 2^1<br />3 = 3^1<br />4 = 2^2<br />5 = 5^1<br />6 = 2^1 * 3^1<br />7 = 7^1<br />8 = 2^3<br />9 = 3^2<br />10 = 2^1 * 5^1<br /><br />The LCM is the product of the highest exponents for each of those bases.<br />So the LCM in this case = 2^3 * 3^2 * 5^1 * 7^1 = 8*9*5*7 = 2,520.<br /><br />Our answer is one less than that number, so our answer is 2,519. <br /><br />You can do the division with each of those to check that the remainders are correct.Josh D.https://www.blogger.com/profile/13718628093230589490noreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-7153625456579842232015-10-22T16:37:51.805+05:302015-10-22T16:37:51.805+05:30119119Unknownhttps://www.blogger.com/profile/00679546541005453164noreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-63499139863949406612015-10-22T16:01:19.310+05:302015-10-22T16:01:19.310+05:30Remainder on dividing by any K (K from 2 to 10) is...Remainder on dividing by any K (K from 2 to 10) is K -1. So the number can be lcm(1,2,3,...10)-1 = 2519Movinhttps://www.blogger.com/profile/17764206130587621002noreply@blogger.com