tag:blogger.com,1999:blog-3802979373213475425.post7984689205167854417..comments2018-02-18T04:29:09.413+05:30Comments on Critical Thinking Puzzles: Crazy guy on the airplaneEldhose Babyhttps://plus.google.com/111638910038568381260noreply@blogger.comBlogger24125tag:blogger.com,1999:blog-3802979373213475425.post-61091080424422838342012-02-21T09:00:43.649+05:302012-02-21T09:00:43.649+05:30n!= the # of possibile outcomes
(n-1)!= # of outc...n!= the # of possibile outcomes<br /><br />(n-1)!= # of outcomes that will give you your seat<br /><br /># of favorable outcomes/ # possible outcomes = P(getting you seat) <br /><br />P(getting your seat) = n-1!/n!<br />(n-1)!/n! = 1/n<br />P(getting your seat = 1/n... 1/100Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-30946229573523674602011-07-12T01:38:59.564+05:302011-07-12T01:38:59.564+05:30the first guy has a 1 in 100 chance to choose the ...the first guy has a 1 in 100 chance to choose the right seat if he does then everyone else will sit in their assigned seat because they will all be available so for the last person its 1/100Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-73197375081065581062011-07-06T09:14:43.541+05:302011-07-06T09:14:43.541+05:30where is the like button? the pilot answer is extr...where is the like button? the pilot answer is extremely funny!Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-90026635144368497692011-05-09T03:32:39.644+05:302011-05-09T03:32:39.644+05:30100%... you are the pilot100%... you are the pilotAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-71190342147955972942011-04-14T02:07:50.948+05:302011-04-14T02:07:50.948+05:30Wow. I was way off my game on this riddle. My hu...Wow. I was way off my game on this riddle. My humble apologies....Dogtag114noreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-71025705324734778742011-03-18T15:22:15.230+05:302011-03-18T15:22:15.230+05:30What is wrong with 1/3+1/6=1/2What is wrong with 1/3+1/6=1/2Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-776840895006362632011-03-06T05:31:00.251+05:302011-03-06T05:31:00.251+05:30Ok it is 50/50.Ok it is 50/50.Dogtag114noreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-86239566366610894732011-03-05T18:32:54.803+05:302011-03-05T18:32:54.803+05:30I believe it is 49% = 50% minus the 1/100 chance ...I believe it is 49% = 50% minus the 1/100 chance that the first guy picks the right seat.<br /><br />Secret Squirrel had an error in his proof where he stated 1/3+1/6 = 1/2.Dogtag114noreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-38646600370499485132011-02-28T03:45:17.199+05:302011-02-28T03:45:17.199+05:30well if steve initially chooses his correct seat a...well if steve initially chooses his correct seat at random, then everyone following would get there correct seat. including yourself. so it cant be 0Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-86084087144038102932011-02-15T20:35:20.200+05:302011-02-15T20:35:20.200+05:30This comment has been removed by the author.V N Phttps://www.blogger.com/profile/00644001721322319188noreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-69752665726679891562011-01-17T11:21:42.528+05:302011-01-17T11:21:42.528+05:30You could work it our for 100 passengers but it...You could work it our for 100 passengers but it's easier if you do it for smaller numbers and see if there is a general case that can be applied to greater numbers.<br /><br />For 2 passengers it is obvious that you have a 1/2 chance of getting your seat.<br /><br />For 3, 1/3 of the time Steve will pick his own seat and you'll get yours; 1/3 of the time he'll pick your seat (and you don't); and 1/3 of the time he'll take passenger #2's seat. Now the problem is exactly the same as for 2 passengers, with passenger #2 now playing the role of Steve. We already know the chance of you getting your seat in this case is 1/2.<br /><br />So the possible outcomes are:<br />Steve picks his own seat / you get yours - 1/3<br />Steve picks #2's seat / you get yours - 1/3 * 1/2 = 1/6<br />Steve picks #2's seat / you don't get yours - 1/3 * 1/2 = 1/6<br />Steve picks your seat / you don't get yours - 1/3<br /><br />Total chance of you getting your seat: 1/3 + 1/6 = 1/2<br /><br />Next, you do the same thing with 4 passengers. Again, Steve can either pick his own seat or yours with equal probability. If he picks one of the others, the problem is now equivalent to the 3-passenger problem with it's 1/2 probability of you getting your seat.<br /><br />Do the same for 5 passengers and it reduces to the same as for 4 and so on.<br /><br />So, no matter how many passengers there are, as long as the plane is full and there is only one "Steve", your chances of getting your own seat are 1/2.<br /><br />The answer of 1/100 (presumably obtained by (99/100 * 98/99 *...*2/3 * 1/2) would only be true if *all* of the passengers chose their seat at random. In fact, it would be zero for me because I would not get on a plane full of crazy passengers.Secret SquÃ¯rrelnoreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-5572758961530418442011-01-16T14:04:29.087+05:302011-01-16T14:04:29.087+05:30I think zero is correctI think zero is correctAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-86061691440196287212011-01-15T02:45:43.225+05:302011-01-15T02:45:43.225+05:30is it 0?? the flight is full..is it 0?? the flight is full..karthiknoreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-2574383692394333622011-01-14T21:24:40.459+05:302011-01-14T21:24:40.459+05:30So which is the right answer? I was thinking 1/2 ...So which is the right answer? I was thinking 1/2 as well. Between the last seat, and the seat the guy is in.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-91412436801692172682011-01-12T20:32:12.484+05:302011-01-12T20:32:12.484+05:30That depends, do I really want my assigned seat? I...That depends, do I really want my assigned seat? If it is a good one I will use my ticket to keep it!Tracyhttp://www.sciencewithme.com/noreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-85707225429039137222011-01-12T01:32:00.417+05:302011-01-12T01:32:00.417+05:30Great site!!!
Carry on the Excellent work..<b><i>Great site!!!<br />Carry on the Excellent work..</i></b>Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-72534265466865048942011-01-11T12:17:35.482+05:302011-01-11T12:17:35.482+05:301/2<b>1/2</b>Babu vincenthttps://www.blogger.com/profile/16720816763813773975noreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-50531057767551401032011-01-11T12:16:38.919+05:302011-01-11T12:16:38.919+05:301/21/2Babu vincenthttps://www.blogger.com/profile/16720816763813773975noreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-47319502036968703142011-01-11T12:16:14.162+05:302011-01-11T12:16:14.162+05:301/501/50Babu vincenthttps://www.blogger.com/profile/16720816763813773975noreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-88536275550039757502011-01-11T01:38:45.810+05:302011-01-11T01:38:45.810+05:301/100
if steve guess the right seat out of 100 the...1/100<br />if steve guess the right seat out of 100 then the last seat will be ursAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-67430557626357020902011-01-06T13:59:11.302+05:302011-01-06T13:59:11.302+05:30He should check his seat number which is on his ti...He should check his seat number which is on his ticket and take his seat!Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-68881201636929586632011-01-05T14:35:12.936+05:302011-01-05T14:35:12.936+05:301/1001/100Babu vincenthttps://www.blogger.com/profile/16720816763813773975noreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-16718105045856060592011-01-04T19:53:42.023+05:302011-01-04T19:53:42.023+05:30100% because I kept my ticket!100% because I kept my ticket!Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-3802979373213475425.post-80635239869234178612011-01-04T17:07:04.499+05:302011-01-04T17:07:04.499+05:30The probability is .5 u can either sit on your pla...The probability is .5 u can either sit on your place or notAvishekhttps://www.blogger.com/profile/18134404710428476055noreply@blogger.com