A man wanted to get into his work building, but he had forgotten
his code. However, he did remember five clues.
These are what those clues were:
# The fifth number plus the third number equals fourteen.
# The fourth number is one more than the second number.
# The first number is one less than twice the second number.
# The second number plus the third number equals ten.
# The sum of all five numbers is 30.
What were the five numbers and in what order?
8 comments:
The numbers in order are
7, 4, 6, 5, and 8.
suppose digits are: A B C D E
1) E + C =14
2) B + 1 = D
3) A = 2 * B - 1
4) B + C = 10
5) A + B + C + D + E = 30
start with 5
Using 1
A + B+ D + 14 = 30
A + B+ D = 16
Using 3
2B -1 + B + D = 16
3*B + D = 17
using 2)
3*B + B + 1 = 17
B=4
Using 2
D = 5
Using 3
A= 7
using 4
C= 6
using 1
E = 8
7 4 6 5 8
Get all the numbers in terms of B, add them all and solve for B.
A B C D E F
A = 2B-1
B = B
C = 10 -B
D = 1 + B
E = 14 - C ==> Sub C=10-B. C=B+4
Add them all up, and solve for B. You get B=4.
Substitute B in all the terms, you get,
7 4 6 5 8
u can just start with a bit of guessing and after 2 minutes u have 74658!!
not that hard
74658
Ok, so he can't remember his five-digit code, but he can remember 5 complicated equations about the individual didgits? BWA HA HA HA HA!!!
9 6 5 5 5 is the answer, I think
not that hard 74658
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