How many people must be there if all but 2 are named Smith, all but 2 are named Jones, and all but 2 are named Wilson?
November 4, 2011
How many people are there?
How many people must be there if all but 2 are named Smith, all but 2 are named Jones, and all but 2 are named Wilson?
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23 comments:
2...
3 - one Smith, one Jones and one Wilson.
3
3
3 :P
3
3
total 6. 2 smith, 2 jones and 2 wilson
only 2 ..none of them is smith,jones or wilson
Must be 3
6? or 2?
3 quite easy one
Its 3 smith, jones and Wilson
how it will be 3
A minimum of 3
3??
3??
3
explain pls
There's 1 Smith, and two others - Jones & Wilson (all but two are Smith).
There's 1 Jones, and two others - Smith & Wilson (all but two are Jones).
There's 1 Wilson, and two others - Smith & Jones (all but two are Wilson).
Its 3 smith, jones and Wilson
It's 3. The mathematical way to find this out would be:
Equation: P= s+j+w
Key: P= # of people s= # of people named smith j= # of people named Jones w= # of people named wilson
So... is all but 2 are named Smith then s= P-2, if all but 2 are named jones then j= P-2, if all but 2 are named wilson then w= P-2
P then eqauls: P= (P-2) + (P-2) + (P-2)
P= 3P-6
-2P= -6
P= 3
The correct answer is 2 or 3? Can it be 2 considering that none of them is named smith or Jones or Wilson?
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