100 people standing in a circle in an order 1 to 100.
No.1 has a sword. He kills next person (i.e.no. 2 )and
gives sword to next to next (i.e no.3).
All person does the same until only 1 survives.
Which number survives at the last?
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19 comments:
73
No.73 will survive
99
reybo1 says 97
73
is there an intelligent way of finding solution.I created a binary tree,with each branch having common scheme for elements.
57
Looks like 73 to me. I just created the numbers 1-100 and started crossing them off.
Person number 1
#1
the first person #1 because no one killed #1
# 1 was the person who sarted the patteren
First... mass genecide of even numbers (no offense to our even numbered friends).
Last death is 93 at the hands of 61.
No elegant solution other than excel model...
73
73.
start at 1 +2
next set +4
next set +8
next set +16
next set +32.
9+32+32=73 End.
73. Just make a list of numbers and cross off every other number till only one is left. 73 is the last man standing.
In the first round 99 kills 100 and gives sword to person no1 and then in second round 97 kills 99 and gives sword to 1 ...so like this..doesn't 1 keeps alive everytime? How do we cancel the nos such that 1 gets killed??
1. All evens die.
2. 1, 5, 9, 13, 17, 21, 25, 29, 33, 37, 41, ... , 93, 97 live (97 kills 99)
3. 1, 9, 17, 25, 33, 41, 49, 57, 65, 73, 81, 89, 97 live (97 kills 1)
4. 9, 25, 41, 57, 73, 89 live (89 kills 97)
5. 9, 41, 73 live (73 kills 89)
6. 9, 73 live (73 kills 9)
7. 73 is still alive. However, 73 is the next number, and thus 73 kills 73. The sword disintegrates into the null and infinite.
You can only kill person next to you... so 73 is the lucky one to be alive with Excalibur! Now try with 1 kills not 2 but 3 and gives it to 4 and so on.... have fun!
The solution is number 73
I find the solution by building a Javascript algorithm that can be found at People with Sword Around a Circle
Hope it helps
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