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December 22, 2014

Bird flying in a square

People A,B,C,D, each is at each edge of a square, the square side is 100 meter. A moves to B, B moves to C, C moves to D, D moves to A at speed 1m/s. Simultaneously a bird flies from A to B, then to C, then to D, then to A and so on. The bird meets D for the first time at the 30 second, when will it meet D for the third time?

4 comments:

Anonymous said...

110 seconds.

Aftwr meeting D at 30 seconds, the bird has flown 330 m for a speed of 11 m/s.

To catch D, the bird must fly 400 m + the distance travelled by D, in the same time.

Thus,
Tbird = (400 +distD)/11mps
TD = distD/1mps

Solving TD = Tbird gives

distD = 40m - time = 40 sec

Thus, they meet for a second time at 30 + 40 = 70 sec.

Similarly they meet again after
70+ 40 sec = 110 sec.

D has travelled 110 m, the bird has travelled 1220 m.

December 23, 2014 at 12:08 AM
Anonymous said...

Happy Holidays, Love your website.

December 23, 2014 at 12:09 AM
Ram said...

110 seconds

December 23, 2014 at 6:29 PM
Mayur said...

1st crossing at :- 30 sec
2nd crossing at :- 40 sec
3rd crossing at :- 40 sec

i.e. a bird will take 110sec for the third time.

December 26, 2014 at 2:55 PM

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