Critical Thinking Puzzles: Put any Mathematical signs and get 6.

January 21, 2015

Put Any Mathematical signs and get 6:
1 1 1 = 6
2 2 2 = 6
3 3 3 = 6
4 4 4 = 6
5 5 5 = 6
6 6 6 = 6
7 7 7 = 6
8 8 8 = 6
9 9 9 = 6

Unknown said...: (1+ 1 + 1)! = 6
2 + 2 + 2 = 6
3x3-3 = 6
√4 + √4 + √4
5/5 + 5
6 + 6 – 6
7 – 7/7
∛8 + ∛8 + ∛8
(92/9) - √9
Bonus:
(0!+0!+0!)! = 6

*Superscrip not working, so the 2 in the nine line is squared.; January 22, 2015 at 5:28 PM
Noggin Noddlebright said...: Using numerals in operator functions (such as squares or cubed roots) may seem like cheating.

√√8 + √√8 + √√8
9-(9/√9); January 26, 2015 at 12:58 AM
Anonymous said...: √√8 + √√8 + √√8 = 5 and a bit. Doesn't work.; January 28, 2015 at 7:46 PM
Noggin Noddlebright said...: Yes, I realized later that √√8 was not 2 - stupid mistake.

(√(8+(8/8))! works though.; February 1, 2015 at 2:48 AM
Anonymous said...: |{1,{1},{{1}}}|! = 6
|{2,{2},{{2}}}|! = 6
|{3,{3},{{3}}}|! = 6
|{4,{4},{{4}}}|! = 6
|{5,{5},{{5}}}|! = 6
|{6,{6},{{6}}}|! = 6
|{7,{7},{{7}}}|! = 6
|{8,{8},{{8}}}|! = 6
|{9,{9},{{9}}}|! = 6; February 3, 2015 at 11:05 PM
Unknown said...: Brackets are floor function.

(1+1+1)!=6
2+2+2=6
(3-3+3)!=6
4+4-√4=6
5+5/5=6
6+6-6=6
7-7/7=6
|[-(√√8+√√8+√√8)]|=6
(√9-√9+√9)!=6

I love the floor function. Very nice way to round.; February 11, 2015 at 10:45 AM

Critical Thinking Puzzles