A shop sells 1 chocolate at Rs:1 each, You can exchange 3 wrappers for a chocolate. If you have Rs:15, then how many chocolates can you totally get ?
Answer is 22 Chocolates
1) with Rs:15 you will get 15 chocolates --->15 wrappers
2)15 wrappers /3 = 5 chocolates ------> 5 wrapers
3) 5 wrappers /3 = 1 chocolate +2 wrappers------->3 wrappers
4) 3 wrappers / 3 = 1 chocolate
Total chocolates = 15+5+1+1 =22
Check also : How many Chocolates you will get if you have Rs. 45
Answer is 22 Chocolates
1) with Rs:15 you will get 15 chocolates --->15 wrappers
2)15 wrappers /3 = 5 chocolates ------> 5 wrapers
3) 5 wrappers /3 = 1 chocolate +2 wrappers------->3 wrappers
4) 3 wrappers / 3 = 1 chocolate
Total chocolates = 15+5+1+1 =22
Check also : How many Chocolates you will get if you have Rs. 45
7 comments:
15+5+1+1 = 22
15 chocs,
15 wafers /3 = 5 wafer= s -> 5 chocs,
5 wafers / 3 = 1 choc + 1 wafer
now 2 left wafers + 1 wafer = 3 wafers -> 1 choc
totally 15+5+1+1 = 22 chocs and 1 wafer being left with you.
Rs = 1
You have 15 Rs
You can therefor purchase 15 chocolates.
The value of the "wrappers" is another distraction and has nothing to do with the equation
Randy, we need to consider the value of wrappers also ....
answer is 22 Chocolates
Explanation
1) with Rs:15 you will get 15 chocolates --->15 wrapers
2)15 wrapers /3 = 5 chocolates ------> 5 wrapers
3) 5 wrapers /3 = 1 chocolate +2 wrapers------->3 wrapers
4) 3 wrapers / 3 = 1 chocolate
Total chocolates = 15+5+1+1 =22
22
ambiguous it doesn't say that buying a chocolate gives you a wrapper. but if it implies that then the answer is definately 22
15rs che 45
45 wrappers return kele 15 milale
45+15=60
Again 15 wrappers return kele 5 milale
60+5=65,
5 wrappers madhun 3 return melee we get 1
Total=66
Urlele 2+1=3 ret and melee we get 1
66+1=67
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