A Shop was selling 3 chocolates for Re. 1 and if you return three wrappers you get one free. If so, how many chocolates can you get for Rs. 45 ?

## January 8, 2016

### A Shop Selling 3 Chocolates for Re. 1 Puzzle

A Shop was selling 3 chocolates for Re. 1 and if you return three wrappers you get one free. If so, how many chocolates can you get for Rs. 45 ?

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## 24 comments:

45*3+45+15+5+1+1 = 202

Wrong

13

13

157?

157

45+15+5+1+1=67

202 is correct

<202>

is correct

4 x 45

or...(45*3)+45+15+5+1

45 x 3 = 145

145 chocolates ==> 145 wrappers ==>

45 chocolates ==> 45 wrappers ==>

15 chocolates ==> 15 wrappers ==>

5 chocolates ==> 5 wrappers ==>

1 chocolate ( 2 wrappers ) ==> 3 wrappers ==>

1 chocolate

----

212 chocolates

kuny

135

45

15

5

1

1

=202..?

Ans 180

45*3+45+15+5+2 = 202

197

201

45*3==>135+45(from 135 wrappers)+15(from 45 wrappers)+5(from 15 wrappers)+1(from 3 wrappers)+1(from 2 wrappers from 5 + last wrapper) = 202

202 is correct

202 is correct

less than or equal to 202

Re. 1 (if it continues to Re. 99 & e,f,g,h,i,j,k,l,m,n,o,q,p,r,s)

up to Rs. 45 he/she will buy 2833 chocolates.

202 is the correct ans

If we g by the english alphabet...

"e" is the 5th letter of the alphabet

"s" is the 19th letter of the alphabet

"e" goes into "s" 3.8 times. So 3.8 Re = a single Rs

If Re. 1 gets you 3 chocolates then Re. 45 would get you 135 chocolates.

Since 3.8 Re is equal to a single Rs, Rs. 45 would get you 513 chocolates.

From the initial 513 chocolates you get 171 free.

From the 171 you get 57 free.

From the 57 you get 19 free.

From the 19 you get 6 free and have one left over.

From the 6 you get 2 free.

So you would be able to buy 513 chocolates with Rs. 45 and receive 256 free chocolates for a total of 769 chocolates.

I'm pretty sure this riddle is supposed to say $1 and $45 for 202 chocolates...

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