A boy has few toffees.he is about to eat them when
one of his friend comes and asks him to share.He divides
them equally into 2 parts without any toffee remaining.
Then one more boy comes so he divides into 3 equal parts
without any toffee remaining.Then one more boy comes so
he divides into 4 equal parts without any toffee remaining.
Then one more boy comes so he divides into 5 equal parts
without any toffee remaining.Then one more boy comes so
he divides into 6 equal parts without any toffee remaining.
Then one more boy comes so he divides into 7 equal parts
but one toffee remains.
HOW MANY TOFFEES DID THE BOY ORIGINALLY HAVE?
7 comments:
i thnk answer is 120????
721
Yea, 120 .. (not 721 again lol)
120 is the minimum that satisfies the criteria.
540, 960, (+420)... all work too.
Secret Squïrrel
least such number is 120
i.e. a multiple of 2,3,4,5 & 6 but remainder 1 when divided by 7
I think 5040 is the real answer
Asanka Manohara.
120
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