2 batsman r on 94. 2 balls remaining & 7 runs to win.
and both the batsman make their century & win match How?
March 24, 2009
2 Batsman are on 94 problem ?
2 batsman r on 94. 2 balls remaining & 7 runs to win.
and both the batsman make their century & win match How?
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First guy hits the ball for 3 runs, and fielder throws the ball which goes to the boundary as overthrows. Umpire calls one run short. So 2 runs run by batsmen and 4 overthrows, so 6 runs 1 century completed. Also, as the batsmen ran 3 runs, the other guy will be on strike for the next ball. He hits six and match is won and both get centuries!!!!!!!!!!!!!!!!
Could I get this in English first?
me 2.. i dun even understand the question..
Out of the 2 deliveries left, one is the last delivery of an over. So one batsman hits a sixer to complete his century. The sides change since the over is completed. Now our second batsman hits a sixer too!!!
The first batsman hits the ball and starts running. the two batsmen make 6 runs, running between the wickets (while overthrows keep happening). while taking the seventh run,the two batsmen cross each other, but the first batsman who had hit the six gets run out.In the next ball the second batsman hits a six.
lol.. what the hell...?
first ball is 4 by first batsman,
second ball , its goes for 3 but because of not touching
the screeze it is added only two for first batsman, so he
completed 100 and also strike goes for second batsman;
last ball second batsman will have one six;
What about if they didn't were born to win?
What about if they never manage to accomplish it?
Easier on turns!
Thanks for the help in this question. I did not know it.
1st batsman hit six, next ball he gets run out, now crease changed, now 2nd batsman hit 6. Yeah
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