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hmm is it possible that your riddle is wrong? :sor am i misreading it?because:Y+N = Yand T+E=Twould make that both N and E are equal to 0 if i'm correct?might be messed up with missing spaces or something?kind regards
29786 850+ 850_____31486A) Y + 2N = Y, --> N = 0B) T + 2E = 10 + T, --> E = 5C) 1 + R + 2T must be > 20 because W + 2 has to be > 10 in order for their to be a remainder of 1 to add to F in order to get S. After making that observation it is just a matter of trial and error substituting large enough values for T and R to satisfy condition C while making sure that S = F + 1.
@LisaThat's exactly how I did it. :-)
@lisathis is the best solution.....without any fucking hit n trial(digit 0) 2N = 0 (mod 10)(digit 1) 2E = 0 (mod 10) no carry from digit 0 possibleTherefore N=0 and E=5.Then O=9 and I=1 requiring two carries. Further S=F+1.Digit 2 no gives the equationR + 2T + 1 = 20 + XThe smallest digit left is 2. So X>=2 Therefore R + 2T >= 21. As not both R and T can be 7one of then must be larger that is 8.We are left with some case checkings.Case R=8:Then T>=6.5 that is T=7 and X=3. There are no consecutive numbers left for F and S.Case T=8:Then R>=5 and as 5 is in use R>=6.Case R=6: As X=3 there are no consecutive numbers left.Case R=7: As X=4 we get F=2 and S=3. The remaining digit 6 will be Y.Therefore we get a unique solution.29786 +850 +850-----31486
thts wat i hav got lik lisa
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