A man wanted to get into his work building, but he had forgotten

his code. However, he did remember five clues.

These are what those clues were:

# The fifth number plus the third number equals fourteen.

# The fourth number is one more than the second number.

# The first number is one less than twice the second number.

# The second number plus the third number equals ten.

# The sum of all five numbers is 30.

What were the five numbers and in what order?

## 8 comments:

The numbers in order are

7, 4, 6, 5, and 8.

suppose digits are: A B C D E

1) E + C =14

2) B + 1 = D

3) A = 2 * B - 1

4) B + C = 10

5) A + B + C + D + E = 30

start with 5

Using 1

A + B+ D + 14 = 30

A + B+ D = 16

Using 3

2B -1 + B + D = 16

3*B + D = 17

using 2)

3*B + B + 1 = 17

B=4

Using 2

D = 5

Using 3

A= 7

using 4

C= 6

using 1

E = 8

7 4 6 5 8

Get all the numbers in terms of B, add them all and solve for B.

A B C D E F

A = 2B-1

B = B

C = 10 -B

D = 1 + B

E = 14 - C ==> Sub C=10-B. C=B+4

Add them all up, and solve for B. You get B=4.

Substitute B in all the terms, you get,

7 4 6 5 8

u can just start with a bit of guessing and after 2 minutes u have 74658!!

not that hard

74658

Ok, so he can't remember his five-digit code, but he can remember 5 complicated equations about the individual didgits? BWA HA HA HA HA!!!

9 6 5 5 5 is the answer, I think

not that hard 74658

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