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November 4, 2011

How many people are there?


How many people must be there if all but 2 are named Smith, all but 2 are named Jones, and all but 2 are named Wilson?

23 comments:

André Meneses said...

2...

ivanatora said...

3 - one Smith, one Jones and one Wilson.

Rajesh said...

3

Ron said...

3

InvincibleApurva said...

3 :P

Anonymous said...

3

Jyotirmoy Chakraborty said...

3

Anonymous said...

total 6. 2 smith, 2 jones and 2 wilson

Anonymous said...

only 2 ..none of them is smith,jones or wilson

shae said...

Must be 3

Anonymous said...

6? or 2?

dileep_ratna said...

3 quite easy one

antiderivative calculator said...

Its 3 smith, jones and Wilson

Anonymous said...

how it will be 3

Anonymous said...

A minimum of 3

Midgley's Photography/HSMPS said...

3??

Midgley's Photography/HSMPS said...

3??

Anonymous said...

3

Mehul Chauhan said...

explain pls

Varghese Philip said...

There's 1 Smith, and two others - Jones & Wilson (all but two are Smith).
There's 1 Jones, and two others - Smith & Wilson (all but two are Jones).
There's 1 Wilson, and two others - Smith & Jones (all but two are Wilson).

Anthony Ewing said...

Its 3 smith, jones and Wilson

Anonymous said...

It's 3. The mathematical way to find this out would be:
Equation: P= s+j+w
Key: P= # of people s= # of people named smith j= # of people named Jones w= # of people named wilson
So... is all but 2 are named Smith then s= P-2, if all but 2 are named jones then j= P-2, if all but 2 are named wilson then w= P-2

P then eqauls: P= (P-2) + (P-2) + (P-2)
P= 3P-6
-2P= -6
P= 3

Anonymous said...

The correct answer is 2 or 3? Can it be 2 considering that none of them is named smith or Jones or Wilson?