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January 21, 2015

Put any Mathematical signs and get 6.

Put Any Mathematical signs and get 6:
1 1 1 = 6
2 2 2 = 6
3 3 3 = 6
4 4 4 = 6
5 5 5 = 6
6 6 6 = 6
7 7 7 = 6
8 8 8 = 6
9 9 9 = 6

6 comments:

Eric Langevin said...

(1+ 1 + 1)! = 6
2 + 2 + 2 = 6
3x3-3 = 6
√4 + √4 + √4
5/5 + 5
6 + 6 – 6
7 – 7/7
∛8 + ∛8 + ∛8
(92/9) - √9
Bonus:
(0!+0!+0!)! = 6

*Superscrip not working, so the 2 in the nine line is squared.

Noggin Noddlebright said...

Using numerals in operator functions (such as squares or cubed roots) may seem like cheating.

√√8 + √√8 + √√8
9-(9/√9)

Anonymous said...

√√8 + √√8 + √√8 = 5 and a bit. Doesn't work.

Noggin Noddlebright said...

Yes, I realized later that √√8 was not 2 - stupid mistake.

(√(8+(8/8))! works though.

Anonymous said...

|{1,{1},{{1}}}|! = 6
|{2,{2},{{2}}}|! = 6
|{3,{3},{{3}}}|! = 6
|{4,{4},{{4}}}|! = 6
|{5,{5},{{5}}}|! = 6
|{6,{6},{{6}}}|! = 6
|{7,{7},{{7}}}|! = 6
|{8,{8},{{8}}}|! = 6
|{9,{9},{{9}}}|! = 6

Thomas Riley said...

Brackets are floor function.

(1+1+1)!=6
2+2+2=6
(3-3+3)!=6
4+4-√4=6
5+5/5=6
6+6-6=6
7-7/7=6
|[-(√√8+√√8+√√8)]|=6
(√9-√9+√9)!=6

I love the floor function. Very nice way to round.