How much does the baby weigh if the mother weighs 100 pounds
more than the combined weight of the baby and the dog,
and the dog weighs 60 percent less than the baby?
Provided the combined weight of all 3 is 170 pounds.

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## 12 comments:

Not enough information to solve. 3 variables require three equations.

Actually, there is enough information to solve the puzzle.

M=100+B+D

D=0.4*B

M+B+D=170

B=25

D=10

M=135

Mother 135 lbs

Baby 25 lbs

Dog 10 lbs

There are three equations. Read again

Mother 135 lbs

Baby 25 lbs

Dog 10 lbs

There are three equations

Ok, now it's solvable.

Mother: 100 lb

Baby: 50 lb

Dog: 20 lb

M = MOTHER WEIGHT

B = BABY WEIGHT

D + DOG WEIGHT

Given Equations:

=================

Eqn No 1 ==> M = 100 + B + D

Eqn No 2 ==> D = B - B X 0.6

Eqn No 3 ==> B + D + M = 270

Solving for B+D in Eqn No 1

============================

B + D + M = 170

B + D = 170 - M

Replacing B + D in Eqn No 1

===========================

M = 100 + 170 - M

2M = 270

M = 135

Now Mother Weight, M = 135

==========================

Replacing M in Eqn No 3

=======================

B + D + 135 = 170

B + D = 170 - 135

B + D = 35

D = 35 - B

Replacing this D value in Eqn 2

===============================

35 - B = B - 0.6B

35 = B + B - 0.6B

35 = 2B - 0.6B

35 = 1.4B

35/1.4 = B

350/14 = B

25 = B

Baby Weight, B = 25

Dog Weight, D = 10

Mother Weight, M = 135

============================================

M = MOTHER WEIGHT

B = BABY WEIGHT

D + DOG WEIGHT

Given Equations:

=================

Eqn No 1 ==> M = 100 + B + D

Eqn No 2 ==> D = B - B X 0.6

Eqn No 3 ==> B + D + M = 270

Solving for B+D in Eqn No 1

============================

B + D + M = 170

B + D = 170 - M

Replacing B + D in Eqn No 1

===========================

M = 100 + 170 - M

2M = 270

M = 135

Now Mother Weight, M = 135

==========================

Replacing M in Eqn No 3

=======================

B + D + 135 = 170

B + D = 170 - 135

B + D = 35

D = 35 - B

Replacing this D value in Eqn 2

===============================

35 - B = B - 0.6B

35 = B + B - 0.6B

35 = 2B - 0.6B

35 = 1.4B

35/1.4 = B

350/14 = B

25 = B

Baby Weight, B = 25

Dog Weight, D = 10

Mother Weight, M = 135

============================================

M = MOTHER WEIGHT

B = BABY WEIGHT

D + DOG WEIGHT

Given Equations:

=================

Eqn No 1 ==> M = 100 + B + D

Eqn No 2 ==> D = B - B X 0.6

Eqn No 3 ==> B + D + M = 270

Solving for B+D in Eqn No 1

============================

B + D + M = 170

B + D = 170 - M

Replacing B + D in Eqn No 1

===========================

M = 100 + 170 - M

2M = 270

M = 135

Now Mother Weight, M = 135

==========================

Replacing M in Eqn No 3

=======================

B + D + 135 = 170

B + D = 170 - 135

B + D = 35

D = 35 - B

Replacing this D value in Eqn 2

===============================

35 - B = B - 0.6B

35 = B + B - 0.6B

35 = 2B - 0.6B

35 = 1.4B

35/1.4 = B

350/14 = B

25 = B

Baby Weight, B = 25

Dog Weight, D = 10

Mother Weight, M = 135

============================================

Anonymous said...

Not enough information to solve. 3 variables require three equations.

--->You have 3 equations. Read it again.

Anonymous said...

Not enough information to solve. 3 variables require three equations.

There are 3 equations. Read it more carefully.

Baby -25pound

Dog- 10 pound

Mother-135 pound

Has someone hacked Squirrel's account, or has he finally got one wrong????

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